-5x^2-27x+56=0

Solution for -5x^2-27x+56=0 equation:

-5x^2-27x+56=0

a = -5; b = -27; c = +56;
Δ = b2-4ac
Δ = -272-4·(-5)·56
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-43}{2*-5}=\frac{-16}{-10}
=1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+43}{2*-5}=\frac{70}{-10}
=-7
$